Backhand, 203 bytes

""###:::[[[:::::::::)))))))))888999***EEE666***333+++ssscccjjjlll222%%%'''ccc***333+++xxx(((sssaaa'''OOO'''www'''iii'''eee'''!!!'''   '''TTT'''hhh'''aaa'''ttt'''   '''hhh'''uuu'''rrr'''ttt'''!!!rrr~~~HHH

Attempt This Online! or with a char removed.

Note: This is based on Jo King's answer to a similar question.

Every character here is repeated three times as a form of radiation hardening (aside from the leading "), since Backhand by default executes every third instruction. I'll explain the deduplicated code:

"#:[:::)))89*E6*3+scjl2%'c*3+x(sa'O'w'i'e'!' 'T'h'a't' 'h'u'r't'!r~H # Wrap around, pushing every third character of the code aside from `"`, forwards then backwards
 #                                                                   # NOP      
  :[                                                                 # Duplicate and increment the # into a "
    :::)))                                                           # Push three copies of the char to the other stack
          89*E                                                       # If it's not equal to 72 ("H")
              6*3+scj                                                # Jump back to the start of the loop
                     l2%'c*3+                                        # Is the length of the pushed code odd (char missing)?
                             x(s                                     # Switch to the other stack
                                a'O'w'i'e'!' 'T'h'a't' 'h'u'r't'!    # If so, push "\nOwie! That hurt!"
                                                                 r~  # Remove a redundant `"`
                                                                   H # Terminate and print the contents of the stack as a string