g | x | w | all
Bytes Lang Time Link
057Perl 5 p240327T152001ZXcali
014Vyxal240828T063617Zemanresu
nanRuby161220T054754ZValue In
100Python170101T205135ZCormac
093JavaScript161220T215056ZWashingt
197C#161222T210253ZErresen
207Haskell161220T213749Zarchaeph
01605AB1E161219T234453ZAdnan
200Java 7161220T154556ZKevin Cr
239C#161220T131031Zsatibel
nan161220T053118ZBrad Gil
084Perl 6161220T005844Zsmls
102PHP161219T235204ZTitus
025Pyke161220T000626ZBlue
030MATL161219T231453ZLuis Men
036V161219T230738ZDJMcMayh

Perl 5 -p, 62 57 bytes

@a=christmas=~/./g;s|\pL|lc$&eq$a[$i%9]&&++$i?$&:$&^$"|ge

Try it online!

Vyxal, 14 bytes

‛ß₌£Nƛ⇩¥h=[N&Ǔ

Try it Online! Outputs as a char list, s flag formats into string.

   £           # Store into the register
‛ß₌            # compressed string "christmas"
    N          # Swap case of each letter
     ƛ         # Over each letter
          [    # If
      ⇩        # The letter, lowercased
         =     # equals
       ¥h      # The first char of the register
           N   # Switch the case again
            &Ǔ # And shift the first char of the register to the end

Ruby, 63+1 = 64 bytes

Uses the -p flag.

i=0;gsub(/./){|c|c=~/#{"christmas"[i%9]}/i?(i+=1;c):c.swapcase}

Python 100 bytes

def a(s,i=0,g=''):
 for c in s:a=c.lower()=='christmas'[i%9];i+=a;g+=[c.swapcase(),c][a]
 return g

JavaScript, 122 118 114 107 104 93 bytes

f=
s=>s.replace(/./g,c=>(k=c.toLowerCase())=='christmas'[i%9]?++i&&c:k!=c?k:c.toUpperCase(),i=0)


F=s=>console.log(f(s))
F(`Hello World!`)
F(`I like pie :)`)
F(`hELP my KeYboarD
       iS BROKEN`)
F(`cHRISTMAS IS COMING REALLY SOON!`)
F(`C is the first letter in cHRISTMAS`)

C# 197 bytes

Not going to win with this, but hopefully the smallest C# implementation that works...

string C(string s){int i=0,j=0;var r="";for(;i<s.Length;){char c=s[i++],o=(char)32;if(c=="christmas"[j]|c=="CHRISTMAS"[j])j=j>7?0:j+1;else if(c>64&c<91)c+=o;else if(c>96&c<123)c-=o;r+=c;}return r;}

Explanation:

string C(string s)
{
    // define our two index ints
    // i for indexing across the input string
    // j for indexing across christmas
    int i = 0, j = 0;

    // r is our return string
    var r = "";

    // declare our loop
    // skip the initialisation and afterthought
    for (; i < s.Length;)
    {
        // get our current character c, and increment index i
        // initial our offset char o (difference between upper and lower case)
        char c = s[i++], o = (char)32;

        // check if c is the current character in our christmas bug
        if (c == "christmas"[j] | c == "CHRISTMAS"[j])
            // increment j (or reset to 0)
            j = j > 7 ? 0 : j + 1;

        // else if c is an upper case char
        else if (c > 64 & c < 91)
            // add our offset to make it lower case
            c += o;

        // else if c is lower case
        else if (c > 96 & c < 123)
            // subtract our offset to make it upper case
            c -= o;

        // append c to our return string r
        r += c;
    }

    return r;
}

Haskell, 222 207 Bytes

import Data.Char
s=(+(-65)).ord
f=(`divMod`32).s
l=[['a'..'z'],['A'..'Z']]
c=cycle$map s"CHRISTMAS"
k _[]=[]
k(a:b)(x:y)|isAlpha x=let(d,m)=f x in if(m==a)then(x:k b y)else(l!!d!!m:k(a:b)y)|1>0=x:k(a:b)y
main=interact$k c

updated:

import Data.Char
s=(+(-65)).ord
k _[]=[]
k(a:b)(x:y)|isAlpha x=let(d,m)=s x`divMod`32 in if(m==a)then(x:k b y)else([['a'..'z'],['A'..'Z']]!!d!!m:k(a:b)y)|1>0=x:k(a:b)y
main=interact$k$cycle$map s"CHRISTMAS"

How it works:

s=(+(-65)).ord

s x = ASCII value of x - ASCII value of 'A'

f=(`divMod`32).s

f (s x) = (0,s x) for uppercase, (1, (s x-32)) for lowercase

l=[['a'..'z'],['A'..'Z']]

parallel list of letters, indexable by f (lowercase->1->uppercase, uppercase->0->lowercase)

c = cycle $ map s "CHRISTMAS"

infinite list of the ascii values of uppercase christmas repeated

k _ []=[]

base case

k (a:b) (x:y) | isAlpha x = let (d,m) =f x
                             in if m == a
                                then x : k b y
                                else (l!!d)!!m : k (a:b) y
              | 1 > 0 = x : k (a:b) y

return non-alphanumeric characters, and either keep the letter if its s-value is the same as the current letter of christmas (going to the next letter), otherwise convert it to the other case and proceed

main=interact$k c

IO

05AB1E, 16 bytes

Thanks to Emigna for saving a byte and fixing a bug!

vyÐl'ŒÎ¾èQi¼ëš}?

Explanation:

vy                # For each character in the string...
  Ð               #   Triplicate that character
   l              #   Convert to lowercase
    'ŒÎ           #   Compressed version of "christmas"
       ¾          #   Push the counting variable (let's call this N)
        è         #   Get the nth character of "christmas", with modular indexing
         Qi   }   #   If equal...
           ¼      #      N += 1
            ë     #   Else...
             š    #      Swapcase
               ?  #   Print that character

Uses the CP-1252 encoding. Try it online!

Java 7, 200 bytes

String c(char[]a){String r="";int i=0,s;Character l='a';for(char c:a)if((s="christma".indexOf(l=l.toLowerCase(c)))==i|i>7&s==4){r+=c;i=i>7?0:i+1;}else r+=l.isUpperCase(c)?l:l.toUpperCase(c);return r;}

Ugly, but it works.. Can definitely without any doubt be golfed more.. I'm rusty..

Ungolfed:

String c(char[] a){
  String r = "";
  int i = 0,
      s;
  Character l = 'a';
  for(char c : a){
    if((s = "christma".indexOf(l = l.toLowerCase(c))) == i) | i > 7 & s == 4){
      r += c;
      i = i > 7
           ? 0
           : i+1;
    } else{
      r += l.isUpperCase(c)
       ? l
       : l.toUpperCase(c);
    }
  }
  return r;
}

Test code:

Try it here.

class M{
  static String c(char[]a){String r="";int i=0,s;Character l='a';for(char c:a)if((s="christma".indexOf(l=l.toLowerCase(c)))==i|i>7&s==4){r+=c;i=i>7?0:i+1;}else r+=l.isUpperCase(c)?l:l.toUpperCase(c);return r;}

  public static void main(String[] a){
    System.out.println(c("i CAN HARDLY WORK LIKE THIS please GET ME A NEW KEYBOARD FOR cHRISTMAS".toCharArray()));
    System.out.println(c("Hello World!".toCharArray()));
    System.out.println(c("I like pie :)".toCharArray()));
    System.out.println(c("hELP my KeYboarD\niS BROKEN".toCharArray()));
    System.out.println(c("cHRISTMAS IS COMING REALLY SOON!".toCharArray()));
    System.out.println(c("C is the first letter in cHRISTMAS".toCharArray()));
  }
}

Output:

I Can HaRdly work lIke thiS PLEASE geT Me A new keyboard for ChriStmas
hELLO wORLD!
i LIKE PIE :)
Help MY kEyBOARd
Is broken
cHRISTMAS is Coming really soon!
C IS ThE FIrST LETTER iN ChriSTMAS

C# 239 chars

var s=Console.ReadLine().ToCharArray();int j=0,i=0;var c="christmas";for(;j<s.Length;j++)if(s[j]==c[i%9]|s[j]==(c[i%9]-32))i++;else if(s[j]>64&s[j]<91)s[j]=(char)(s[j]+32);else if(s[j]>96&s[j]<123)s[j]=(char)(s[j]-32);Console.WriteLine(s);

more explicit version:

var s = Console.ReadLine().ToCharArray();
int j = 0,i = 0;
var c = "christmas";
for (var j = 0; j < s.Length; j++)
   if (s[j] == c[i%9]|s[j] == (c[i%9] - 32))// non case sensitive compare with c 
      i++;//next char in christmas
   else
      if (s[j] > 64 & s[j] < 91)//if between A and Z
         s[j] = (char)(s[j] + 32);//convert to a-z
      else
         if (s[j] > 96 & s[j] < 123)//if between a and z
            s[j] = (char)(s[j] - 32);//convert to A-Z
Console.WriteLine(s);

this is a pretty naïve solution, and probably can be improved (maybe we can allow implicit conversion to char?).

it assumes to be inside a function, reads from the console (stdin), and writes to it (stdout).

edit: Char.IsUpper(s[j]) is 2 bytes longer than s[j]>64&&s[j]<91, Char.ToUpper is longer than my version too.

Perl 6, 80 bytes

{my$i=0;S:g{.?<!{'christmas'.comb[$i%9]eq$/.lc&&++$i}>}=$/eq$/.lc??$/.uc!!$/.lc}

Try it

{   # bare block lambda with implicit parameter 「$_」

  my $i = 0;             # counter

  S                      # substitute and return ( implicitly against 「$_」 )
  :global
  {
    .                    # any char
    ?                    # work around a bug where 「$/」 doesn't get set

    <!{                  # fail this match if this block returns True
      'christmas'.comb\  # a list of the characters of 「christmas」
      [ $i % 9 ]         # grab a char from the list
      eq                 # is it equal to
      $/.lc              # the lowercase version of the char
      &&                 # if so
      ++$i               # increment 「$i」 ( result is True )
    }>

  }

  =                      # for each matched char

  $/ eq $/.lc            # is it lowercase?
  ?? $/.uc               # the uppercase it
  !! $/.lc               # otherwise lowercase it
}

Perl 6, 84 bytes

{my $i=0;[~] (.lc~~"christmas".comb[$i%9]??(++$i&&$_)!!.ord>90??.uc!!.lc for .comb)}

PHP, 113 110 102 bytes

while($o=ord($c=$argv[1][$i++]))echo chr(32|$o==ord(christmas[$k%9])?$o|0&$k++:ctype_alpha($c)*32^$o);

takes input from first command line argument. Run with -r.

breakdown

while($o=ord($c=$argv[1][$i++]))// loop through string characters
    echo chr(
        32|$o==ord(christmas[$k%9]) // if $c equals next character in "christmas"
            ?$o|0&$k++              // no change, increase "christmas" index
            :ctype_alpha($c)        // else if $c is a letter
                    *32^$o          // toggle bit 5 of the ascii code
        );

Pyke, 31 25 bytes

FD.dґ~o@Dl3+{DIoK)R!Il3

Try it here!

MATL, 36 30 bytes

"@tk'schristma'H)=?HQXHx}Yo]&h

Strings with newlines need to be defined by concatenating with the ASCII code 10 (see example in the link with the test cases).

Try it online! Or verify all test cases.

Explanation

"              % Implicit input of a string. For each character in that string
  @            %   Push current character
  tk           %   Duplicate and convert to lowercase
  'schristma'  %   Push string. This is 'Christmas' in lowercase and circularly
               %   shifted such that the 'c' is in the second position
  H            %   Push contents of clipboard H, which is initiallized to 2.
               %   This value will be gradually increased when a new character
               %   from the the sequence is found
  )            %   Get character from 'schristma' at that (modular) position
  =            %   Are they equal?
  ?            %   If so
    HQ         %     Push contents of clipboard H and add 1
    XHx        %     Copy into clipboard K and delete
  }            %   Else
    Yo         %     Change case
  ]            %   End
  &h           %   Concatenate stack contents horizontally. This gives a string 
               %   with all characters processed up to now
               % Implicit end. Implicit display
          

V, 38, 36 bytes

ÄVumaOchristmasòÉf2x`a@"maj~HòHdjV~

Try it online! (contains input and expected output for comparison)

When I first saw this, I thought it would be extremely easy. In fact, if it were not for the "christmas" bug, this would just be 2 bytes: V~. The christmas bug makes it significantly harder, for a very hacky answer.

As usual, here is a hexdump:

00000000: c456 756d 614f 6368 7269 7374 6d61 731b  .VumaOchristmas.
00000010: f2c9 6632 7860 6140 226d 616a 7e48 f248  ..f2x`a@"maj~H.H
00000020: 646a 567e                                djV~