| Bytes | Lang | Time | Link |
|---|---|---|---|
| 101 | AWK | 250930T145239Z | xrs |
| 045 | MATL | 161208T201710Z | Luis Men |
| 130 | Java 8 | 170613T091709Z | Kevin Cr |
| 371 | Visual Basic | 170612T215059Z | polyglot |
| 116 | tcl | 170111T213357Z | sergiol |
| 135 | C# | 161209T140011Z | Snowfire |
| 121 | C | 170119T182744Z | Abel Tom |
| 109 | Clojure | 170120T004845Z | Carcigen |
| 080 | TIBasic | 170119T153206Z | Timtech |
| 040 | Noodel | 170111T185214Z | tkellehe |
| 149 | Python 3 | 161223T221039Z | python-b |
| nan | PHP | 161209T161152Z | thisisbo |
| nan | 161213T161056Z | Tom Laza | |
| 110 | Racket | 161213T034302Z | rnso |
| 250 | ForceLang | 161213T051050Z | SuperJed |
| 082 | *><> Starfish | 161208T193612Z | redstarc |
| 104 | Bash | 161209T175932Z | Hydraxan |
| 079 | PHP | 161209T130106Z | user5917 |
| nan | HTML + JS ES6 | 161210T000141Z | darrylye |
| 108 | Octave | 161209T123424Z | Stewie G |
| 094 | R | 161209T214817Z | bouncyba |
| 133 | Mathematica | 161209T182324Z | Kelly Lo |
| 108 | MATLAB | 161209T160028Z | hwm |
| 087 | Groovy | 161208T175528Z | Magic Oc |
| 103 | C | 161208T203323Z | nmjcman1 |
| 118 | F# | 161209T140647Z | pmbanka |
| 109 | Javascript ES6 | 161208T203000Z | Ismael M |
| 065 | Powershell | 161208T191309Z | colsw |
| 185 | Batch | 161208T202759Z | Neil |
| 067 | Perl 6 | 161208T193722Z | Brad Gil |
| 112 | Python 2 | 161208T175449Z | Kade |
AWK, 101 bytes
END{for(srand();i++<100;system("sleep "rand()%.75))printf"\rloading "substr("\\|/-",i%4+1,1)FS i" %"}
MATL, 45 bytes
101:"'loading'O'-\|/'@)O@qVO37&hD750Yr100/&Xx
Example run in the offline compiler:
Or try it at MATL Online!
Explanation
101: % Push array [1 2 ... 101]
" % For each
'loading' % Push this string
O % Push 0. When converted to char it will be displayed as a space
'-\|/' % Push this sring
@) % Modular index into this string with iteration index
O % Push 0
@q % Iteration index minus 1
V % Convert to string
O % Push 0
37 % Push 37, which is ASCII for '%'
&h % Concatenate horizontally into a string, Numbers are converted to char
D % Display
750Yr % Random integer with uniform distribution on [1 2 ... 750]
100/ % Divide by 100
&Xx % Pause that many tenths of a second and clear screen
% End (implicit)
Java 8, 130 bytes
()->{for(int n=0;n<101;Thread.sleep((long)(1+Math.random()*750)))System.out.print("\rloading "+"-\\|/".charAt(n%4)+" "+n+++" %");}
Explanation:
()->{ // Method without parameter nor return-type
for(int n=0;n<101; // Loop from 0 to 100
Thread.sleep((long)(1+Math.random()*750)))
// And sleep randomly 1-750 ms
System.out.print( // Print:
"\r // Reset to the start of the line
loading " // Literal "loading "
+"-\\|/".charAt(n%4)+" " // + the spinner char & a space
+n++ // + the number (and increase it by 1)
+" %"); // + a space & '%'
// End of loop (implicit / single-line body)
} // End of method
Output gif:
Visual Basic, 371 Bytes
module m
sub main()
Dim s as Object
for i as Integer=0 to 100
Select Case new System.Random().next(0,9)
Case 0
s=1
Case 1
s=2
Case 2
s=5
Case 3
s=10
Case 4
s=15
Case 5
s=20
Case 6
s=25
Case 7
s=50
Case 8
s=500
End Select
Console.SetCursorPosition(0,0)
console.write("loading "+"-\|/"(i mod 4)+" "+i.tostring+" %")
system.threading.thread.sleep(s)
next
end sub
end module
Expanded:
module m
sub main()
Dim s as Object
for i as Integer=0 to 100
Select Case new System.Random().next(0,9)
Case 0
s=1
Case 1
s=2
Case 2
s=5
Case 3
s=10
Case 4
s=15
Case 5
s=20
Case 6
s=25
Case 7
s=50
Case 8
s=500
End Select
Console.SetCursorPosition(0,0)
console.write("loading " + "-\|/"(i mod 4) + " " + i.tostring + " %")
system.threading.thread.sleep(s)
next
end sub
end module
tcl, 116
set i 0;time {lmap c {- \\ | /} {puts -nonewline stderr "\rloading $c $i%";after [expr int(187*rand())]};incr i} 100
Playable in http://www.tutorialspoint.com/execute_tcl_online.php?PID=0Bw_CjBb95KQMOXoybnVSOVJEU00
C#, 170 149 135 Bytes
()=>{for(int i=0;i++<=100;System.Threading.Thread.Sleep(new Random().Next(1,750)))Console.Write($"\rloading {@"-\|/"[i % 4]} {i} %");};
Ungolfed:
static void l()
{
for (int i = 0; i <= 100; System.Threading.Thread.Sleep(new Random().Next(1, 750)))
Console.Write($"\rloading {@"-\|/"[i % 4]} {i} %");
}
I won't guarantee that every character in this is right, please correct me if there are compilation errors. I had to type the whole thing on my phone so I might have accidentally included some errors... ¯_(ツ)_/¯
I hope you guys forgive me that
Tested it on my PC, works like a charm and I even saved a whole 20 bytes thanks to pmbanka :)
C 126 121 bytes
f(){i=0;char c[]="/-\\|";for(;i<101;i++){printf("\rloading %c %d %% ",c[i%4],i);fflush(stdout);usleep(1000*(rand()%75));}
Ungolfed version:
void f()
{
int i=0;
char c[]="/-\\|";
for(;i<101;i++)
{
printf("\rloading %c %d %% ",c[i%4], i);
fflush(stdout);
usleep(1000*(rand()%75));
}
}
@Carcigenicate @ Mukul Kumar Did not read between the lines there, Thanks! :)
Clojure, 109 bytes
(doseq[[c i](map vector(cycle"\\|/-")(range 101))](print"\rloading"c i\%)(flush)(Thread/sleep(rand-int 751)))
Loops over a list of the range of numbers from 0 to 100, zipped with an infinite list of "\|/-" repeating forever.
; (map vector...) is how you zip in Clojure
; All arguments after the first to map are lists. The function is expected to
; take as many arguments as there are lists. vector is var-arg.
(doseq [[c i] (map vector (cycle "\\|/-") (range 101))]
; \r to erase the old line
(println "\rloading" c i \%)
(Thread/sleep (rand-int 751)))
TI-Basic, 80 bytes
For(I,0,100
For(A,0,randE2
End
Text(0,0,"loading "+sub("-\|/",1+fPart(I/4),1)+" ",I," %
End
The randomness comes from the For( loop (E is scientific E token) and since TI-Basic is interpreted there is also automatically some overhead. Remember that in TI-Basic, lowercase letters and some less common ASCII symbols are two bytes each (so specifically for this program, l o a d i n g sub( \ | % are the two-byte tokens
Noodel, noncompeting 40 bytes
Just going back through old challenges (as in challenges that were made before Noodel) and competing with Noodel to find where it is weak.
Loading¤”ḋḟƇḣ⁺s¤ṡ⁺Ḷ101ạ¤%ɱṠ˲⁺Çṛ749⁺1ḍ€Ḃ
If final output does not matter, then can save 2 bytes.
Loading¤”ḋḟƇḣ⁺s¤ṡ⁺Ḷ101ạ¤%ɱṠ˲⁺Çṛ749⁺1ḍ
Noodel pushes the top of the stack to the screen at the end of the program so by adding the €Ḃ it prevents that from happening.
How It Works
Loading¤”ḋḟƇḣ⁺s¤ṡ⁺Ḷ101ạ¤%ɱṠ˲⁺Çṛ749⁺1ḍ€Ḃ # Main Noodel script.
Loading¤”ḋḟƇḣ⁺s¤ṡ⁺ # Creates the array ["Loading¤-¤", "Loading¤\¤", "Loading¤|¤", "Loading¤/¤"]
Loading¤ # Pushes the string "Loading¤"
”Ƈḟḋḣ # Pushes the array ["-", "\", "|", "/"]
⁺s # Concats "Loading¤" to each element in the array by prepending.
¤ # Pushes a "¤" onto the stack.
ṡ # Pushes
⁺
Ḷ101ạ¤%ɱṠ˲⁺Çṛ749⁺1ḍ # Main loop that creates the animation.
Ḷ101 # Loop the following code 101 times.
ạ # Pushes on a copy of the next animation element from the array.
¤% # Pushes the string "¤%"
ɱ # Pushes on the current count of the number of times that have looped (zero based).
Ṡ # Swaps the two items at the bottom of the stack.
Ė # Pushes the item at the bottom of the stack to the top (which will be the string selected from the array).
²⁺ # Concat twice appending the loop count then the string "¤%" to the string selected from the array.
Ç # Pops the string off of the stack, clears the screen, then prints the string.
ṛ749 # Randomly generate an integer from 0 to 749.
⁺1 # Increment the random number producing a random number from 1 - 750.
ḍ # Pop off the stack and delay for that number of milliseconds.
€Ḃ # Ends the loop and prevents anything else being displayed.
€ # Ends the loop (new line could be used as well)
Ḃ # Destroys the current stack therein, nothing gets pushed to the screen at the end of the program.
<div id="noodel" code="Loading¤”ḋḟƇḣ⁺s¤ṡ⁺Ḷ101ạ¤%ɱṠ˲⁺Çṛ749⁺1ḍ€Ḃ" input="" cols="14" rows="2"></div>
<script src="https://tkellehe.github.io/noodel/noodel-latest.js"></script>
<script src="https://tkellehe.github.io/noodel/ppcg.min.js"></script>
Python 3, 149 bytes
import time,random;f=0;n=0
while n<=100:
print("Loading...","|/-\\"[f],n,"%",end="\r");f+=1
if f>=3:f=0
n+=1
time.sleep(random.uniform(.25,.75))
Similar to Loading... Forever, but I did have to edit my answer from there a lot.
PHP, 90 83 80 78 77 Bytes
77:
The closing ; is not needed.
for(;$i<101;usleep(rand(1,75e4)))echo"\rloading ",'-\|/'[$i%4],' ',$i+++0,'%'
78:
While looking for another workaround to get a 0 initially without initializing the variable I came up with this:
for(;$i<101;usleep(rand(1,75e4)))echo"\rloading ",'-\|/'[$i%4],' ',$i+++0,'%';
Changed back to echo to win a few bytes as I only used printf to force-format as int. By incrementing the incremented $i with 0 I get a valid integer. By using single quotes as string delimiter the backslash does not need to be escaped, resulting in another byte freed
80:
Moving the increment of $i from the last for-section to the prinf gave me another 3 off. (See comments below)
for(;$i<101;usleep(rand(1,75e4)))printf("\rloading %s %d%%","-\\|/"[$i%4],$i++);
83:
Removed init of a variable with the loaderstates.
for(;$i<101;usleep(rand(1,75e4)),$i++)printf("\rloading %s %d%%","-\\|/"[$i%4],$i);
90:
I tried removing the init of $i to gain some bytes, as I had to add quite a few to enable the loader animation. printf adds 2 as opposed to echo, but formatting NULL as an integer results in 0.
for($l='-\|/';$i<101;usleep(rand(0,750)*1e3),$i++)printf("\rloading %s %d%%",$l[$i%4],$i);
107 75 Ruby
-32 thanks to manatwork
Normal
i=0
(0..100).each{|c|
system'clear'
puts"loading #{'\|/-'[i=-~i%4]} #{c} %"
sleep rand*(0.750-0.01)+0.01
}
Golfed
101.times{|c|$><<"\rloading #{'-\|/'[c%4]} #{c} %";sleep rand*0.749+0.001}
Racket 110 bytes
(for((i 101))(printf"Loading ~a ~a % ~n"(list-ref'("-" "\\" "|" "/")(modulo i 4))i)(sleep(/(random 750)1000)))
Ungolfed:
(define(f)
(for ((i 101))
(printf "Loading ~a ~a % ~n" (list-ref '("-" "\\" "|" "/") (modulo i 4)) i)
(sleep (/(random 750)1000))))
Testing:
(f)
(This gif file is showing slower display than actual)
ForceLang, 250 bytes
Noncompeting, requires language features which postdate the question
def D def
D w io.write
D l e+"loading"+s
D z string.char 8
D s string.char 32
D d datetime.wait 750.mult random.rand()
D e z.repeat 24
D n set i 1+i
D k s+n+s+"%"
set i -1
label 1
w l+"-"+k
if i=100
exit()
d
w l+"\"+k
d
w l+"|"+k
d
w l+"/"+k
d
goto 1
I should probably fix some bugs related to string literal parsing soon.
*><> (Starfish), 86 82 bytes
| v1*aoooooooo"loading K"&0"-\|/"
!0x1! +
%$<.0+af{od;?)*aa&:&Soono$&+1:&" %"{o:}
This may be able to be golfed more, but I don't see anything super obvious. It sleeps 100ms, 400ms, or 700ms, if this isn't random enough, let me know!
Thanks to @TealPelican for saving me 4 bytes and making it much more random!
The biggest challenges I found (while still trying to keep it small) were randomness, and actually outputting "loading - 100 %" at the end, instead of just exiting at my nearest convenience :p.
Bash, 162 104 bytes
Modification of Zachary's answer on a related question, with massive improvements by manatwork:
s='-\|/'
for x in {0..100};{
printf "\rloading ${s:x%4:1} $x %%"
sleep `printf .%03d $[RANDOM%750+1]`
}
I had to look up how to do random numbers in bash.
Ungolfed / Explained
s='-\|/'
for x in {0..100}
{
# \r returns the carriage to the beginning of the current line.
# ${s:x%4:1} grabs a substring from s, at index x%4, with a length of 1.
printf "\rloading ${s:x%4:1} $x %%"
# "$RANDOM is an internal bash function that returns
# a pseudorandom integer in the range 0 - 32767."
# .%03d is a dot followed by a base-ten number formatted to 3 places,
# padded with zeros if needed.
# sleep accepts a floating point number to represent milliseconds.
sleep `printf .%03d $[RANDOM%750+1]`
}
PHP, 66 79 bytes
for($i=-1;++$i<101;usleep(rand(1,75e4)))echo"\rloading ","-\\|/"[$i%4]," $i %";
Unfortunately I had to assign $i in order to get it to print '0'.
Use like:
php -r 'for($i=-1;++$i<101;usleep(rand(1,75e4)))echo"\rloading ","-\\|/"[$i%4]," $i %";'
Edits: thanks to Titus confirming exactly what's allowed with Mukul Kumar we can save 3 bytes with a less restricted range, but not all 9 bytes with an unrestricted range. Thanks also for pointing out that I forgot the cycling character and providing a simple solution to do it.
HTML + JS (ES6), 16 + 87 = 103 bytes
(f=_=>a.innerHTML='\\|/-'[i++%4]+` ${i<100&&setTimeout(f,Math.random()*750),i} %`)(i=0)
loading <a id=a>
Octave, 122 120 119 108 bytes
I misread the challenge and created an infinite loader that restarted at 0 once it passed 100. Making it into a one time only loader:
a='\|/-';for i=0:100;clc;disp(['Loading ',a(1),' ',num2str(i),' %']);a=a([2:4,1]);pause(0.749*rand+.001);end
Circulating a, a=a([2:4,1]) was flawr's idea here. Also, saved 2 bytes by skipping the parentheses after rand thanks to MattWH.
R - 94 bytes
for(i in 0:100){cat('\rLoading',c('-','\\','|','/')[i%%4+1],i,'%');Sys.sleep(sample(750,1)/1e3)}
Really nice that sample(750,1) == sample(1:750,1).
Mathematica, 133 Bytes
Dynamic[If[x<100,x++,,x=0];Row@{"Loading ",StringPart["-\|/",1+x~Mod~4]," ",x,"%"},
UpdateInterval:>RandomReal@.75,TrackedSymbols:>{}]
This will run once, assuming x is undefined. Clear@x will restart it.
55 characters tied up in verbosity :/
MATLAB, 108 bytes
function k;for i=0:100;a='-\|/';pause(rand*.749+.001);clc;['loading ' a(mod(i,3)+1) ' ' num2str(i) ' %']
end
Groovy, 113 87 bytes
-36 bytes thanks to lealand
{p=-1;101.times{print"\rLoading ${"-\\|/"[p++%4]} $p%";sleep Math.random()*750as int}}
C 112 103 bytes
Saved 9 bytes thanks to @G. Sliepen. Not very exciting, just a golf of your C++ answer basically. Also not a very exciting random function. I thought about Sleep(c[i%4]), or Sleep(i) but they're not random at all!
#import<windows.h>
i;f(){for(;i<101;printf("\rloading %c %d %%","-\\|/"[i%4],i++),Sleep(rand()%750+1));}
Ungolfed:
#include <windows.h>
int i;
void f() {
for(;i<101;) {
printf("\rloading %c %d %%", "-\\|/"[i%4], i++);
Sleep(rand()%750+1);
}
}
F#, 118 bytes
async{let r=System.Random()
for i in 0..100 do printf"\rLoading %O %d %%""|/-\\".[i%4]i;do!Async.Sleep(r.Next(1,750))}
In order to run this snippet, pass it into Async.Start or Async.RunSynchronously.
Javascript (ES6), 128 118 116 115 112 110 109 bytes
This seems to work perfectly fine, even with this sketchy source of "random" numbers.
(X=_=>setTimeout(i>99||X,1+new Date%750,document.body.innerHTML=`<pre>Loading ${'-\\|/'[i%4]} ${i++}%`))(i=0)
Alternative 1, Javascript + HTML, 16 + 84 bytes
This one uses an already-existing element to display the remaining content:
(X=_=>setTimeout(i>99||X,1+new Date%750,a.innerHTML=`${'-\\|/'[i%4]} ${i++}%`))(i=0)
Loading <a id=a>
Alternative 2, 95 bytes
If I can assume a tab is opened and that you're pasting this into the console:
(X=_=>setTimeout(i>99||X,1+new Date%750,document.title=`Loading ${'-\\|/'[i%4]} ${i++}%`))(i=0)
Instead of showing the HTML, the title of the document will change.
Thank you to @user2428118 for saving 2 bytes!
Powershell, 71 68 65 Bytes
Similar to https://codegolf.stackexchange.com/a/101357/59735
Saved 3 bytes by not being an idiot (left the ... on loading)
-3 thanks to VisualMelon
changed 750 -> 751 to make sure 750 is included.
0..100|%{cls;"loading $("|/-\"[$_%4]) $_ %";sleep -m(random 751)}
Explanation:
0..100|%{ #For range 0-100...
cls #Clear Display
"loading $("|/-\"[$_%4]) $_ %" #Display the current string
sleep -m(random 750) #Sleep random ms up to 750
}
Updated gif
Batch, 185 bytes
@set s=-\!/
@for /l %%i in (0,1,100)do @call:l %%i
@exit/b
:l
@cls
@set c=%s:~0,1%
@set s=%s:~1%%c%
@echo Loading %c:!=^|% %1 %%
@set/aw=%random%%%751
@ping>nul 1.1 -n 1 -w %w%
The timing is fairly poor unfortunately, but Batch doesn't have anything better to use than ping.
Perl 6, 67 bytes
for |<- \ | />xx* Z 0..100 {print "\rloading $_ %";sleep .750.rand}
Expanded:
for
# produce a list of all the pairs of values
|<- \ | /> xx * # a flat infinite list of "clock faces"
Z # zipped with
0 .. 100 # all the numbers from 0 to 100 inclusive
# &zip / &infix:<Z> stop on the shortest list
{
# 「$_」 will look something like 「("/", 39)」
# when it is coerced to a Str, all of its elements
# will be coerced to Str, and joined with spaces
print "\rloading $_ %";
sleep .750.rand
}
Python 2, 119 113 112 Bytes
I had originally gone with the random amount being random()/.75, however the endpoint wouldn't be included. There isn't much difference from this to the other question for the infinite load time except for the randomness and the fact that it actually ends.
import time,random as r
for i in range(101):print'\rLoading','-\|/'[i%4],i,'%',;time.sleep(r.randint(1,750)/1e3)
thanks to Jonathan Allan for saving 6 bytes, and DJMcMayhem for saving a byte!



